Given f = fn -> 2 end g = fn -> 2 end How can I match the result of g with f’s ? If I do it like this, it fails because function calls are not allowed in pattern matching. case g.() do f.() -> 1 4 -> 2, 5 -> 3, _ -> 6 end Note: This is dummy version of what I need to do in my project.…

f_result = f.() case g.() do ^f_result -> 1 4 -> 2, 5 -> 3, _ -> 6 end

kokolegorille July 14, 2019, 2:43am 2

What about this?

case {f.(), g.()} do
  {x, y} -> #whatever
end

8 Likes

Can't use function calls in pattern matching