How capture operators work

Questions / Help
, ,
1

Hello one and all,

can someone explain this line of code.

tbl = [%{"insurance_verification" => 1}, %{"modifications_review" => 1}]
key = "insurance_verification"
Enum.find(tbl, & &1[key])
%{"insurance_verification" => 1}

it works, but I don’t understand how it works.
I have read on the capture operator but how it’s being used here escapes me.
Thanks.

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2

& &1[key] is syntatic sugar for fn x -> x[key] end

3 Likes
3

thanks @eksperimental that’s the piece i did not understand… great

one thing though why the extra & before the function, is that an and function?

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4

The first & is the capture. &(...) is fn ... end
The second & together with the number 1 tell it where the first argument to the function is used.

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5

@lc0815 here are the docs:

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6

& &1[key] can be read like &(&1[key]) but the formatter will remove the parens

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7

great @derek-zhou coming from a C# javascript world, the first & to me meant the AND operator, that’s why it was confusing… thanks

8

ah, now it’s clear… great

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