How do you exit out of erl and iex?

Questions / Help
21

Ah, I see, thanks! In this case you can do i mod in Elixir. It shows all of the module information (and it works for all data types).

We don’t have something that prints a list of all modules but I honestly don’t see that being useful (plus autocompletion is most likely a quicker way to explore which modules are loaded).

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22

Though i mod in iex does some strange things.

iex(11)> i :a
Term
  :a
Data type
  Atom
Reference modules
  Atom
Implemented protocols
  IEx.Info, Inspect, List.Chars, String.Chars
iex(12)> i Bert
Term
  Bert
Data type
  Atom
Raw representation
  :"Elixir.Bert"
Reference modules
  Atom
Implemented protocols
  IEx.Info, Inspect, List.Chars, String.Chars

The module Bert doesn’t exist. Also giving an atom like `:“Elixir.Foo” assumes it is a module name not an atom. Who implements the protocols? If it is the shell why are they listed here as they have nothing to do with the thing being inspected?

23

I think that giving raw representation is useful, as someone can be surprised with fact that :"Elixir.Bert" == Bert. Protocol implementations are implemented for Atom so automatically Bert implements them as well (IEx.Info shows this information AFAIK, Inspect allows calling Kernel.inspect/{1,2} on such value, List.Chars/String.Chars allows usage of such value in charlist/string interpolation and usage of Kernel.to_charlist/1/Kernel.to_string/1 functions).

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24

Right, i works for all data types, not only modules. But if you feed it a module, it will show specific module information. Otherwise it falls back to show only atom specific information.

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