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                  stevensonmt
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								<p>I’m not sure I understand why you expand the universe twice and then take sum of each expanded universe distances and then divide by two. Why not just expand the universe once and sum the manhattan distances of the galaxies once?</p> 
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								<p>I only expanded the universe once for each part of the puzzle. Dividing by two is because for each pair of the galaxies <code>a</code> and <code>b</code>, I calculated the distance between <code>a</code> and <code>b</code> and the distance between <code>b</code> and <code>a</code>. I know I could calculate the distances only once. I just didn’t bother to do that optimization.</p> 
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									<span>Creator of ECSx</span>
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								<p>A quick one today:</p>
<pre data-code-wrap="elixir"><code class="lang-elixir">pairs
|&gt; Enum.map(fn {{x1, y1}, {x2, y2}} -&gt;
  # Distance between two points
  dx = x2 - x1
  dy = y2 - y1

  # Count how many empty rows or columns are in between
  expanded_count =
    Enum.count(state.empty_cols, fn col_idx -&gt;
      col_idx in x1..x2
    end) +
      Enum.count(state.empty_rows, fn row_idx -&gt;
        row_idx in y1..y2
      end)

  # Manhattan distance with the empty rows/columns expanded
  abs(dx) + abs(dy) + expanded_count * (expansion_size - 1)
end)
|&gt; Enum.sum()
</code></pre>
<p>Full solution <a href="https://github.com/APB9785/AoC-2023-elixir/blob/master/lib/advent_2023/day_11.ex" rel="noopener nofollow ugc">here on Github</a></p> 
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