I just noticed something that I admit I should have been notice way more earlier TBH…
Variables are scoped in ifs, conds, cases (and I bet it’s applicable to any block).
An example with a simplified snippet:
def doing_something do
a = 1
...
if some_true_condition do
a = 2
...
end
IO.inspect(a) # > Still 1 even if some_true_condition is true
end
Now I’m even surprised of how I didn’t got any bugs so far related to this behavior I wasn’t aware. Maybe I’ve embraced FP well more than I think (so i’m glad).
But until now I didn’t come across (or maybe I didn’t notice) any resource explaining this behavior.
And it’s a really important behavior!
I searched on hexdocs.pm and looked on almost all the guides pages on elixir-lang and this is the only result I found, a changelog for version 1.3 where the following is stated:
Elixir will now warn if constructs like if , case and friends assign to a variable that is accessed in an outer scope.
And contrary to that there isn’t any warning anymore (on v1.10 btw).
I thought replacing the if construct by assigning from the whole block like so:
a =
if some_true_condition do
...
2
end
But in this case we are still changing the value with nil if some_true_condition is actually false instead of doing nothing.
If you happen to have to do something equivalent (changing a value in a block) how do you handle it?
Also if you have any more information about this behavior, I’m interested to learn more.
Remember that you are not changing the value of a. What you are really doing is creating a new variable with the same name (and deleting the old variable).
FWIW, I find myself using this with Ecto.Multi when operations should only be done sometimes:
multi =
Ecto.Multi.new()
|> Ecto.Multi.insert(:a, some_changeset)
|> Ecto.Multi.update(:b, some_other_changeset)
multi =
if control_variable do
Ecto.Multi.insert(multi, :c, optional_changeset)
else
multi
end
Because in 1.7 or 1.8 the “imperative assignment”, which previously issued the warning and changed the value, got removed.
I do consider this a breaking change in elixir, others say the imperative assignment before was a bug that has been fixed with more than enough time of warning.
TIL that there was the “imperative assignment” in Elixir…
So if I correctly understood, now we have what’s a pattern matching, and a variable binding when a variable is on the left hand side (without the pin ^)… But back then there was an other behavior called “imperative assignment”?
The anonymous function in thing captures the value of foo when it’s initially evaluated in the second expression. Subsequent “reassignment” of foo is really rebinding the name, so the anonymous function retains its original reference.
This behavior is intended to be more ergonomic than Erlang, which uses the pattern-matching approach and allows exactly one assignment / binding for a name. In that style, the example above is:
Your first example is interesting because it’s the opposite of a closure.
And for a FP language it makes actually total sense (because of side effects free immutability etc.)
But now I’m here is there any closure mechanism in Elixir?
Regarding for example Clojure which is also FP, do they have closures? (I always assumed that the name had something to do with closures…)
iex(5)> x = 10
10
iex(6)> fun = fn y ->
...(6)> y + x
...(6)> end
#Function<7.91303403/1 in :erl_eval.expr/5>
iex(7)> fun.(4)
14
iex(8)> x = 2
2
iex(9)> fun.(4)
14
Note how rebinding the value of x on line iex(8) didn’t change the output of fun. fun closed over the variables it referred to.
Well I was talking about the mechanism provided in closures where the parent scope is still available even the scope happening after the closure definition.
In Elixir the parent scope is available but only the scope until the closure, not after, which is not really a closure then. Or not the one I’ve learned…
For instance in your example x in the parent scope is available in the function but it’s somehow frozen to that moment (with the value of 10). So when x is modified after the function definition (it becomes 2), it’s still available (hence being a closure) but not with its current value (2), only the old one at that moment (10), so the function is not really a closure.
I mean at least closures in JavaScript work like this (but I guess it’s the same for all the other languages when talking about closures).
You can easily try the following in the developer console of you browser (here an example output in Chrome).
What you’re proving is precisely that rebinding isn’t mutability. The function closes over the value of x. That value isn’t changed when you rebind x. If it changed in the function then x is in fact not immutable. Javascript does not have immutability, so it behaves the way you observe. Closures in immutable languages behave the way you observed in Elixir.
def parsed(string) do
# some other code here
#...
# Problem: I need to parse xml document with multiple broken datetime formats
# to_date and to_date_time returns either value or nil
#
# string - source value
# value - parsed one
value = value || to_date_time(string)
value = value || if to_date(string), do:
to_date_time("#{string}T00:00:00+03:00")
value = value || if String.contains?(string, "+"), do:
String.replace(string, "+", "T00:00:00.000+") |> to_date_time()
value || string
end