Kafftum
Would this code be tail call optimized?
def loop do
inner = fn func, idx, propulsor ->
if idx === 1000 do
propulsor + 1
else
:timer.sleep(1000)
func.(func, idx + 1, propulsor)
end
end
outer = fn func, idx ->
# This should approximately turn out to be 24 hours
if idx === 96 do
IO.puts("Updating Cache")
InstagramApi.main()
func.(func, 0)
else
# Generates new index after a timeout of 1000 seconds
new_idx = inner.(inner, 0, idx)
func.(func, new_idx)
end
end
outer.(outer, 0)
end
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al2o3cr
It does not seem to get optimized, based on the following steps.
Start with a file
bleh.ex:Compile it with
elixir bleh.ex. It will print an error message:That’s expected, because the
@compile :Sflag causes the compiler to dump a BEAM-assembly file atbleh.ex.Sand stop.There’s a lot of detail that’s not directly relevant in the assembly; see the BEAM Book for more info. The important thing to look for is the definitions of the functions.
The closures for
outerandinnerare compiled to functions named-loop/0-fun-1-and-loop/0-fun-0-respectively; you can check by looking at thefunc_infoline that shows where they came from in the source.inneris the shorter of the two:The signal that it’s not tail-call optimized is the
call_fun/deallocate/returnsequence.For comparison,
named_innerdoes the same thing but gets different optimization:The assembly instead ends with a
call_last(which also does adeallocate) and noreturnat all.