kasparinho
Bin Counting elements in a collection by updating a counter map is much slower than first grouping the elements by bin and then count each bin.
I would be curious to learn why. My intuition was the opposite, as the ‘reduce’ approach requires only one pass through the input collection.
Example:
iex> range = 1..1_000_000
iex> is_even? = fn x -> rem(x,2) == 0 end
iex> Enum.reduce(range, %{}, fn elem, acc -> Map.update(acc, is_even?.(elem), 1, &(&1 + 1)) end)
%{false: 500000, true: 500000}
is much slower than
iex> Enum.group_by(range, &is_even?.(&1)) |> Map.new(fn {key, list} -> {key, length(list)} end)
%{false: 500000, true: 500000}
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arnomi
My best guess is that the map lookup is the factor that slows down the ‘reduce’ approach. Although you need to traverse the list only once, you need to perform a key lookup on every item. With the group_by approach on the other hand, might have the group lookup better optimized (although I cannot think of a much better optimization out of hand than using a map for looking up the group..)
On my system the difference is, however, also not that significant. The ‘reduce’ approach is about 1.2 times slower…
lpil
For reference, here’s the implementation of
group_by:I too am surprised that this is faster, especially since
group_byreverses the list, adding another iteration.arnomi
Hm.. the following benchmark now shows a different result…
So your original hunch, might be correct after all.
benwilson512
Make sure you are measuring with something like Benchee and not measuring
iex. code constructed iniexis interpreted, which means it will run slower.kasparinho
Indeed, it appears that when running in iex, the ‘group_by’ version gets an unfair advantage, probably because it gets to use a compiled reduce loop behind the scenes, while the ‘reduce’ version has an interpreted reduce loop.
Thank you for your help!