vlad.grb

vlad.grb

I checked on the forum but still didn’t find a response
Is there any way to send a push to socket without channels. LIke my UserSocket is connected and I want to make something Endpoint.brocast("user_socket:foo", "bar", %{"foo" => "bar"})

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aseigo

aseigo

It may be easier to find an answer if you share what effect you are trying to achieve.

Are you trying to send a message to exactly one of the user’s connections? i.e. they have multiple browsers / mobile app connections and you want to send a message to a specific one, but not all the others? Or something else?

vlad.grb

vlad.grb OP

Let’s say each client connects to server using a token, token is self contained according to Phoenix.Token

  1. Assign a user connected to socket
def connect(%{"token" => token}, socket) do
  {:ok, data} = Phoenix.Token.verify(secret, user_salt, token, max_age: 86400)
  {:ok, assign(socket, :user, %{id: token})}
end
  1. Generate a socket id via
def id(socket), do: "socket.users:#{socket.assigns[:user].id}"

Then somewhere in code send to socket.users:[user_id] some data. Let’s say I opened mobile app and web page with user_id equals to 1 then when I call something like Endpoint.broadcast_to_socket("socket:users:[user_id]")

aseigo

aseigo

Sorry, but I do not quite understand what the question is :confused:

What you described is how it works: given the id/1 function, you can use that in Endpoint.broadcast, e.g.:

MyApp.Endpoint.broadcast("users_socket:" <> user_id, "mymessage", %{})

And then all the connections with user_id would receive that message.

vlad.grb

vlad.grb OP

Are you sure that I am able to do this without connection to any channel?

aseigo

aseigo

Here are the docs for Phoenix.Socket.id/1. It has that exact example there :slight_smile: Give it a try!

vlad.grb

vlad.grb OP

Yeah. I did
If I send hardcoded disconnect as per example it drops connection
But if it looks like

TheAPp.Web.Endpoint.broadcast("socket.users:1", "Hello", %{})

nothing happens
Still the question is that possible to send some piece of data to the client without channels using a socket id
P.S. Without channel means no channel modules at all and no joining

aseigo

aseigo

Looking into it more, you do apparently need to connect to a channel. :frowning: sorry for the noise.

However, you can easily create a users: channel that does not require any special auth:

  def join(<<"user:", id :: binary>>, payload, socket) do
    if socket.assigns.user.id == id do
      send(self(), :after_join)
      {:ok, socket}
    else
      {:error, %{reason: "unauthorized"}}
    end
  end

.. or similar.

and then you can broadcast to the channel. Is there a specific reason you are avoiding connecting to the channel?

vlad.grb

vlad.grb OP

That’s the point that it hasn’t an extra “connection” when it is already opened socket there for any data.

aseigo

aseigo

Channels do not create an extra network connection. They are multiplexed over the socket. On the server-side channels are quite cheap. So I wouldn’t worry about that.

idi527

idi527

MyApp.Endpoint.broadcast("users_socket:" <> user_id, "mymessage", %{})

I think it would only work for "disconnect". I remember struggling with it here How to put something in a socket's assigns from another process - #7 by idi527

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