dimitarvp
Can we import types and guards from another module?
Given this module:
defmodule A do
@type size :: pos_integer()
defguard is_size(x) when is_integer(x) and x > 0
def default_size(), do: 1
end
…how do we make the below work without prefixes?
defmodule B do
@type t :: %__MODULE__{size: size()}
defstruct [size: default_size()]
def put_size(opts, size) when is_list(opts) and is_size(size), do: Keyword.put(opts, :size, size)
end
Tried import A and require A, both don’t get the job done.
What elementary Elixir lesson I managed to forget?
Marked As Solved
NobbZ
You should be able to import is_size/1 just by doing import A(, only: [is_size: 1]).
You can not import types though. The easiest way is to just alias them.
@type foo :: Foo.foo
Also Liked
RobertDober
You might also group your types into a module like so
defmodule MyApp.Types do
defmacro __using__(_opts) do
quote do
@type greek_t :: :alpha | :beta
@type mystruct_t :: MyApp.MyStruct.t # Beware of circulars here!!
end
end
...Last Post!
RobertDober
You might also group your types into a module like so
defmodule MyApp.Types do
defmacro __using__(_opts) do
quote do
@type greek_t :: :alpha | :beta
@type mystruct_t :: MyApp.MyStruct.t # Beware of circulars here!!
end
end
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