dimitarvp
Given this module:
defmodule A do
@type size :: pos_integer()
defguard is_size(x) when is_integer(x) and x > 0
def default_size(), do: 1
end
…how do we make the below work without prefixes?
defmodule B do
@type t :: %__MODULE__{size: size()}
defstruct [size: default_size()]
def put_size(opts, size) when is_list(opts) and is_size(size), do: Keyword.put(opts, :size, size)
end
Tried import A and require A, both don’t get the job done.
What elementary Elixir lesson I managed to forget?
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NobbZ
You should be able to import
is_size/1just by doingimport A(, only: [is_size: 1]).You can not import types though. The easiest way is to just alias them.
dimitarvp
Yeah. I just import the guards and prefix the types. Seems there’s no actual seamless way to import everything in one go without any prefixes. Thank you.
RobertDober
You might also group your types into a module like so