omerss2311
Capturing a function with default arguments?
Hey! I have a function defined with default arguments like so:
def my_func(arg1, arg2 \\ %{}, arg3 \\ false)
I want to pass it as a variable, so I’m capturing it as &my_func/3. However, I want to be able to invoke it with only one or two arguments as well, but that gives an error saying “function with arity 3 called with one argument”. Is there a way to do this?
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D4no0
Default arguments are just a syntactic sugar that transforms into functions with different arity:
def my_func(arg1, arg2 \\ %{}, arg3 \\ false)
# arg2 = %{} and arg3 = false
def my_func(arg1)
# arg3 = false
def my_func(arg1, arg2)
# no default arguments
def my_func(arg1, arg2, arg3)
So if you choose my_func/3, then you are required to pass all arguments when calling it, if you want to avoid passing all the arguments use either my_func/1 or my_func/2.
LostKobrakai
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