noelob
Hi,
I’ve created a simple cluster by opening 2 IEX sessions on two different machines, and I can see the the nodes are clustered:
iex(dev@127.0.0.1)11> Node.list [:this, :visible]
[:"suv@127.0.0.1", :"dev@127.0.0.1"]
When I try running a simple process on the other node, I get this error:
iex(dev@127.0.0.1)7> caller = self()
#PID<0.115.0>
iex(dev@127.0.0.1)8> Node.spawn(:"suv@127.0.0.1", fn -> send(caller, {:response, 1+2}) end)
#PID<14963.130.0>
11:43:45.064 [error] Process #PID<14963.130.0> on node :"suv@127.0.0.1" raised an exception
** (BadFunctionError) function #Function<43.125776118/0 in :erl_eval.expr/6> is invalid, likely because it points to an old version of the code
:erlang.apply/2
iex(dev@127.0.0.1)9> nil
The error implies :erl_eval.expr/6 is missing, so my first guess was differing versions of Elixir and/or Erlang/OTP on each node, but both have elixir 1.15 and OPT 26 as far as I can tell:
Node A:
iex(dev@127.0.0.1)6> System.build_info
%{
version: "1.15.5",
date: "2023-08-28T11:58:30Z",
otp_release: "26",
build: "1.15.5 (compiled with Erlang/OTP 26)",
revision: "9fd97c4"
}
Node B:
iex(suv@127.0.0.1)15> System.build_info
%{
version: "1.15.8",
date: "2024-11-12T06:54:38Z",
otp_release: "26",
build: "1.15.8 (compiled with Erlang/OTP 26)",
revision: ""
}
When I use tab completion on :erl_eval.expr in IEX there is no :erl_eval.expr/6. Any idea what I might be doing wrong?
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ruslandoga
What happens if you try
?
Re
erl_evalin#Function<43.125776118/0 in :erl_eval.expr/6>I think it just means that the anonymous function was defined in IEx. It might or might not mean thaterl_evalis the problem. It might as well beKernel.send/1, if that module / function were updated between 1.15.5 and 1.15.8, which they probably were, at least in “version”.noelob
That worked, thanks!
For my own curiosity, how could I verify where the issue might lie? Look at the Kernel.send source code for each of the Elixir versions or is there a better way?
ruslandoga
I would guess that the closures capture module versions (MD5 by default) in addition to module and function names and since they are different in different versions of Elixir, it results in an error. And maybe sending
Node.spawn(:"suv@127.0.0.1", Kernel, :send, [caller, {:response, 1+2}])doesn’t concern itself with module versions and just runsapply(Kernel, :send, [caller, {:response, 1+2}])so it works across Elixir versions. But it can possibly produce different results from if this was executed locally. But I guess that’s usually expected with distributed systems.ruslandoga
erlang — OTP 29.0.2 (erts 17.0.2) seems to support this guess:
That version seems to be stored in
:new_uniqattribute. Maybe it does some rolling hash of the versions of all the modules mentioned in the function body.noelob
When spawning a remote process like this, does the ‘work’ (1+2 in this case) get evaluated on the local node?
I’d like the ‘work’ to be evaluated on the remote node, and when I replace
1+2withNode.self(), it appears thatNode.self()is evaluated locally, and that the remote node is sending the already computed value back to the local node:I’m a relative Elixir noob, so not quite grasping how to make the remote node do the work
Thanks for your help
ruslandoga
Arguments (it’s just a normal list) are “evaluated” on the calling node, the function is executed on the remote node.
It’s the same as:
You can make the called function process its args and then that part would be handled by the remote node too:
:erpc.callhere just executes the function remotely and sends back the results, similar to yourNode.spawnexample withsend. I just wanted to mention it as it’s a pretty useful module.noelob
Cool, that’s what I figured. So you either need code on the remote node which you can invoke from the local node, or pass a function to the remote node (assuming both nodes have compatible versions).
Thanks for the tip on
:erpc.call, that looks pretty useful