spammy

spammy

Is it possible to match multiple parameters to a single function body? So for:

def foo("a" = word) do
  word
end
def foo("b" = word) do
  word
end
def foo("c" = word) do
  "not a or b!"
end

have a single definition for the first two, so something like:

def foo("a" = word) 
    foo("b" = word) do
  word
end
def foo("c" = word) do
  "not a or b!"
end

Showing Posts 1 to 8

kevinschweikert

kevinschweikert

You can use a guard for that

def foo(word) when word in [“a”, “b”] do
end
spammy

spammy OP

What about in the more general pattern matching case? Ie if the pattern is not regular amongst the choices?

def foo(["a", _] = list) 
    foo([_,"b"] = list) do
  list
end
def foo(list) do
  "doesn't start with a or end with b!"
end

Is another helper function with multiple defns the way?

dimitarvp

dimitarvp

For a list starting with something, it’s trivial:

def foo([first | _rest]) when first in ["a", "b"] do
end

For a list ending with something, it’s more involved as the Erlang lists are single-linked lists (in the C lingo) and you have to traverse the entire list to find the ending:

def foo(list) when is_list(list) do
  if List.last(list) in ["a", "b"] do
    # all good, proceed
  else
    # report an error
  end
end

For this usually people make a public function that does these validations and handles returning errors and then define something like defp do_foo to handle the happy path only.

krasenyp

krasenyp

You are right but I want to add that if one has to check the last element more than once in a blue moon , maybe a list is not the correct data structure.

spammy

spammy OP

Thank you all for the insight but the intent of my post wasn’t about the patterns themselves (they were just arbitrary examples) but how to write a function headers with arbitrary patterns for a single body. Given the responses, I’m assuming it’s not possible. Therefore I guess an answer is:

def foo("a" = word) do: bar(word)
def foo("b" = word) do: bar(word)
defp bar(word) do
   word
end
def foo("c" = word) do
  "not a or b!"
end
krasenyp

krasenyp

Keep in mind bar cannot be between the clauses of another function. It needs to be before or after.

mudasobwa

mudasobwa

Creator of Cure

FWIW, the common convention name for bar should be do_foo as well.

To sum it all up:

def foo("a") do: do_foo("a")
def foo("b") do: do_foo("b")
def foo(word) do
  "not a or b!"
end

defp do_foo(word) do
  word
end
spammy

spammy OP

Perfect, thank you!

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