abdulsattar
How do Ecto bindings work?
How does this work?
query = from u in "users",
where: u.age > 18,
select: u.name
I get that from is a macro, which essentially takes two arguments:
query = from(u in "users",
[where: u.age > 18,
select: u.name])
which makes it more mysterious. u in "users" what does it do? The keyword list has u.age, where does the u come from? How is throwing u not defined exception?
The macro based syntax is also suprising:
"users"
|> where([u], u.age > 18)
|> select([:name])
How does where([u], u.age > 18) not fail with u not defined?
Marked As Solved
minhajuddin
A macro doesn’t execute the code passed in, It gets an AST of the code and it can then do whatever it wants. I haven’t looked at how Ecto actually does this, I am assuming that it gets a hold of the AST and transforms it into a SQL query based on the operators that are being used and then it executes the code. One way to inspect it is by looking at the struct that was returned:
iex(7)> q = from(u in User, where: u.id == 3, order_by: [asc: :id]) |> Map.from_struct
%{
assocs: [],
distinct: nil,
from: {"users", UA.Accounts.User},
group_bys: [],
havings: [],
joins: [],
limit: nil,
lock: nil,
offset: nil,
order_bys: [
%Ecto.Query.QueryExpr{
expr: [asc: {{:., [], [{:&, [], [0]}, :id]}, [], []}],
file: "iex",
line: 7,
params: []
}
],
prefix: nil,
preloads: [],
select: nil,
sources: nil,
updates: [],
wheres: [
%Ecto.Query.BooleanExpr{
expr: {:==, [],
[
{{:., [], [{:&, [], [0]}, :id]}, [], []},
%Ecto.Query.Tagged{tag: nil, type: {0, :id}, value: 3}
]},
file: "iex",
line: 7,
op: :and,
params: []
}
]
}
Here is an example that should give you more clarith around macros, the expression 1 + 2 is never evaluated:
defmodule M do
defmacro add({:+, _, [op1, op2]}) do
quote do
"Add #{unquote(op1)} and #{unquote(op2)} yourself!"
end
end
end
defmodule Test do
def test do
require M
M.add(1 + 3)
end
end
Test.test() |> IO.puts
# => Add 1 and 3 yourself!
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