owaisqayum
While starting a genserver process, I want to give it a name. As you can see in the following example pid is right now acting as a name for the genserver. How can i register table as the name of GenServer.
{:ok, pid} = start_base(). So if i pass table is start_base and then into BaseServer.startlink(), how can i modify my GenServer.start_link(), so that the table acts as the name of GenServer.
Here is my code:
def start_base() do
BaseServer.start_link()
end
def creating_tables(tables_list) do
Enum.map(tables_list, fn table ->
{:ok, pid} = start_base()
IO.puts("Pid of #{table} is #{inspect(pid)} ")
BaseServer.create_table(pid, table)
end)
end
My Genserver:
# client
def start_link do
GenServer.start_link(__MODULE__, [])
end
def create_table(pid, table) do
GenServer.call(pid, {:create_table, table})
end
right now am passing the pid but how can I register it with the table name.
Thanks
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Laetitia
The way to give dynamically a name to a genserver is using the Registry.
You can read more info in:
“GenServer — Elixir v1.20.2”
:your_registry_name may be started under your application supervisor.
owaisqayum
Thank you so much .. i ll have a look at it.
lukaszsamson
You don’t necessarily need a
Registryto do dynamic name registration. If your server name is an atom then the standard mechanism will work fine.Use Registry when you need non standard server name registration (so called via tuple). And Registry is just a one of implementations.
Laetitia
Yes. The standard way is the one you propose. But it generates dynamically atoms. If the goal is to start a lot of genserver on the fly, it could become problematic.
LostKobrakai
To be fair the “standard way” is also a registry. It’s just automatically running and doesn’t need wrapping in a via tuple for being the default. Though now I’m interested if there’s actually a speed difference between the two and if so how much it it.