sadcad
so it’s these two simple lines:
https://hastebin.com/bonopujawa.exs
The first one executes, the second prints to stdout. the output is a and ok.
How can I print a only ?
How can I print ok only ?
In other words, how can I access them separately ?
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Ankhers
Code.eval_string("IO.puts('a')")will print thea. When you doIO.puts(result), that is printing the:ok.sadcad
that prints both..
Ankhers
It does not. Do it in
iexand you will see what is happening.The
{:ok, []}from the first function call is the return value of callingCode.eval_string/3. In this case, you are binding theresultvariable to the atom:ok.In the second line, you are printing out the atom
:ok, which gets printed asok. And then we see:okas the return value of theIO.puts/2call.sadcad
So how would I be able to write
ato stderr for example ? obviously without changing the code ineval_string.Ankhers
To my knowledge, you can’t. The default IO device for the
IO.puts/2function is:stdio. You would need the code written asCode.eval_string("IO.puts(:stderr, 'a')")in order to have it go to stderr.sadcad
Any other way to split them ? maybe using regex ?
benwilson512
What are you trying to do?
sadcad
I write the result to stdout and if I get something like
IO.puts()then I write it’s output to stderr.Like this:
benwilson512
I mean at a high level. This seems like a very unusual requirement, what are you trying to achieve at the big picture level?
sadcad
I simply want to write in case of IO.puts()
Your console output is:and otherwise I’d writeYour returned result is:That’s pretty much what I want to achieve.