chulkilee

chulkilee

How to remove comments from Elixir code?

I found Code.string_to_quoted/2 returns quoted expression, but couldn’t find a way to rebuild it to code. Also, it has all location information and complicated nest format… so it’s doable but doesn’t seem “easy” at the first glance (e.g. no documentation on the structure? )

I already have a shell script to remove any line starting with # (with optional leading white spaces).. but of course that can break things (e.g. # in multiline string)

Any tips?

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NobbZ

NobbZ

You can use Macro.to_string/1/2:

iex(1)> """
...(1)> defmodule M do
...(1)>   # a function
...(1)>   def foo, do: :foo
...(1)> end
...(1)> """
"defmodule M do\n  # a function\n  def foo, do: :foo\nend\n"
iex(2)> Code.string_to_quoted(v(1))
{:ok,
 {:defmodule, [line: 1],
  [
    {:__aliases__, [line: 1], [:M]},
    [do: {:def, [line: 3], [{:foo, [line: 3], nil}, [do: :foo]]}]
  ]}}
iex(3)> v(2) |> elem(1) |> Macro.to_string
"defmodule(M) do\n  def(foo) do\n    :foo\n  end\nend"
iex(4)> IO.puts(v(3))
defmodule(M) do
  def(foo) do
    :foo
  end
end
:ok
kokolegorille

kokolegorille

Maybe sed?

or awk?

awk '!/^ *#/ && NF' file
Schultzer

Schultzer

You are looking for Macro — Elixir v1.20.2

Schultzer

Schultzer

Thats properly because the formatter use Inspect.Algebra — Elixir v1.20.2

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