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Idiomatic Elixir for collecting last item from dynamic list

How to write idiomatic Elixir for the following code in Ruby? The main difficulty here is that the immutable language cannot accumulate items in such way: if my current item does not meet the condition than I want to get the last item which did it before.

result = []
items.each do |item|
  if condition(item)
    result << {value: item, flag: :ok}
  else
    result << {value: result.last, flag: :previous} 
  end
end

UPDATE: I had an error in the code. I have to find last item from result list.

First Post!

bbense

bbense

There’s a couple approaches, if items is always a List, you can write your own reduction. If it might be something else that is still Enumerable, you’ll need to use Enum.reduce. Basically, all “looping” is done with reductions that peel off the head of the loop and then call the function on the tail. If you need state from a previous loop, you put
that in an “acc” or accumulator argument.

Here’s a list based version

def last_true( [], acc,  check_fn)  do
    acc 
end

def last_true( [ head | tail ], acc, check_func ) do 
      case check_func(h) do 
            true -> new_ acc = [ %{value: head, flag: :ok} | acc ]
             -     ->  [ prev_item | _rest ] = acc
                         new_acc = [  Map.put(prev_item, :flag, :previous) | acc ]
      end
      last_true( tail, new_acc, check_func) 
end

Depending on exactly what you want to do, you might need to reverse the output of last_true at this point. There is an optimized erlang function for this case. :lists.reverse. You would call last_true something like this.

   results = last_true(items, [] , &check_fun/1 )

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