I am a beginner making a code with module. Employee module has a struct and a function. Employees have names, id’s, salaries and jobs. I have gotten updating jobs and salaries to work.

I still need for the employee id to update for each new employee. I also want to be able to assign a first and last name for each new employee. I tried to do that following this: https://inquisitivedeveloper.com/lwm-elixir-18/ (‘Packaging Struct Data and Functions’). But for some reason, it didn’t work, even if I copied their code.

Is this possible? Thank you in advance.

defmodule Employee do

    defstruct firstName: "", lastName: "", id: 0, salary: 0, job: :none

    def new() do

        %Employee{}

    end

    def promote(employee) do

        case employee.job do

            :none -> employee = %{employee | job: :coder, salary: 2000}

            :coder -> employee = %{employee | job: :designer, salary: 4000}

            :designer -> employee = %{employee | job: :manager, salary: 6000}

            :manager -> employee = %{employee | job: :ceo, salary: 8000}

        end

    end

	def increment_id(employee) do
		%Employee{employee | id: employee.id + 1}
	end
end

employee = Employee.new("John", "Smith")
IO.puts("Employee name: #{employee.firstName} #{employee.lastName}. ID: #{employee.id}.
Job and salary: #{employee.job}, #{employee.salary}")


employee = Employee.promote(employee)
IO.puts("Employee name: #{employee.firstName} #{employee.lastName}. ID: #{employee.id}.
Job and salary: #{employee.job}, #{employee.salary}")

employee = Employee.promote(employee)
IO.puts("Employee name: #{employee.firstName} #{employee.lastName}. ID: #{employee.id}.
Job and salary: #{employee.job}, #{employee.salary}")

employee = Employee.demote(employee)
IO.puts("Employee name: #{employee.firstName} #{employee.lastName}. ID: #{employee.id}.
Job and salary: #{employee.job}, #{employee.salary}")


employee2 = Employee.new("Jane", "Doe")
IO.puts("Employee name: #{employee2.firstName} #{employee2.lastName}. ID: #{employee2.id}.
Job and salary: #{employee2.job}, #{employee2.salary}")