For every conditional assignment, every time I need to write a new condition. for example-
price_plan["standard_plan"]["monthly"] == 0 ->
price_plan["standard_plan"]["monthly"] != 0 ->
case ready_for_eligible_account do
How can I do the same in 1 conditional case? Also, tell the general way so that I could handle more than 2 conditional case. Your help will be appreciated.
This can be easily rewritten as a simple assignement:
ready = price_plan["standard_plan"]["monthly"] == 0
And this is easier to grasp when written as an
if rather than a
message = if ready, do: "Coupon Validated", else: "Invalid Coupon"
Great. Thank you very much.
Your first expression whas of this kind:
result = cond do
condition -> true
not condition -> false
Which in its nature is very similar
result = if condition, do: true, else: false
Which can always be simplified to
result = condition
The second one is a bit different, but usually, whenever you have a
case matching on
false only, you usually can just replace it by an
if, there might be cases where you want to explicitely
false rather than truthy/falsey checks, then of course you need the
And to be honest, about any 2-clause-
case that matches on an exact value rather than binding names, while the other arm uses
_ can be rewritten into an
if by just using
Kernel.==/2, depending on the semantics you need.