from(q in query,
join:
va in ^from(va in VideoAnalysis,
where: va.id == ^video_id,
limit: 1,
order_by: [desc: :inserted_at]
),
join: v in assoc(va, :video),
where: v.id == ^video_id
)
But soon found that …
** (Ecto.QueryError) ....query.ex:108: queries in joins can only have `where` conditions in query:
from c in Clip,
join: v0 in ^#Ecto.Query<from v in VideoAnalysis, where: v.id == ^7275, order_by: [desc: v.inserted_at], limit: 1>,
join: v1 in assoc(v0, :video),
where: v1.id == ^7275
select: c
trying to figure out how I can query for all the records of a thing through an intermediate record.
IE say I have a VideoAnalysis record that belongs_to a video and has many clips.
How can I query for all the clips of a video analysis if all I know if the video id?
But there is a catch in my case join: video_analysis in assoc(c, :video_analysis), would return multiple records.
Q: How could I make it to where I can limit it to only the newest based on inserted at for VideoAnalysis
in short I’m trying to do all this in the Ecto Query with just one query
if that is even possible
latest_video_analysis =
from va in VideoAnalysis,
where: va.id == ^video_id,
limit: 1,
order_by: [desc: :inserted_at]
from v in Video,
join: va in subquery(latest_video_analysis), on: v.id == va.video_id,
where: v.id == ^video_id
I got that far, though I though it was the same thing I was already doing. That said it does not raise an error, though on the other hand it does not return expected results.
iex(24)> subset_query = from(va in VideoAnalysis,
...(24)> where: va.id == ^video_id,
...(24)> limit: 1,
...(24)> order_by: [desc: :inserted_at]
...(24)> )
#Ecto.Query<from v in VideoAnalysis, where: v.id == ^3, order_by: [desc: v.inserted_at], limit: 1>
iex(25)>
nil
iex(26)> Repo.all(
...(26)> from(c in Clip,
...(26)> join: va in subquery(subset_query),
...(26)> join: v in assoc(va, :video)
...(26)> )
...(26)> )
[debug] QUERY OK source="clips" db=4.4ms queue=0.1ms
SELECT * FROM "video_analyses" AS v0 WHERE (v0."id" = $1) ORDER BY v0."inserted_at" DESC LIMIT 1) AS s1 ON TRUE INNER JOIN "videos" AS v2 ON v2."id" = s1."video_id" [3]
[]
iex(27)>
from(q in query,
join:
va in ^from(va in VideoAnalysis,
where: va.id == ^video_id, # here
limit: 1,
order_by: [desc: :inserted_at]
),
join: v in assoc(va, :video),
where: v.id == ^video_id # and here
)
But there is a catch in my case join: video_analysis in assoc(c, :video_analysis), would return multiple records.
How is that a catch. Given that a video can have multiple clips you would expect the same video analysis to appear with each clip that belongs to the video.
I’m assuming
Clip [0..*] -- [1] Video [1] -- [0..*] VideoAnalysis
The idea is that I only know of a video but I want all the clips found on the newest video_analysis which belongs to the video. the issue is that there are many video_analysis that belong to a given video
What about a subquery in a lateral join then? Ah, it’s not necessary actually. What about this?
latest_video_analysis =
from va in VideoAnalysis,
where: va.video_id == ^video_id,
limit: 1,
order_by: [desc: :inserted_at]
from c in Clip,
join: va in subquery(latest_video_analysis),
where: c.video_analisis_id == va.id
newest_videoanalysis =
from va in VideAnalysis,
order_by: [desc: va.inserted_at],
where: va.video_id == ^video_id,
limit: 1
from clips in Clips,
join: nva in subquery(newest_videoanalysis), on: clips.video_analysis_id == nva.id
You are starting with a video_id - so ultimately the can only be 1 or 0 distinct video_ids - 0 being the case when you can’t find any VideoAnalyses, 1 if there is one or more Video Analyses.
So it seems to boil down to
Give me all video clips if there is at least one Video analysis
No clips if no Video analysis can be found
So your query could be phrased as:
Give me all the Clips for video_id if there is at least one Video Analysis (… which seems odd)
Something along the lines of
Given the set n latest Video Analyses
Get me the distinct set of video_ids
And get me the associated Clips
sounds much more likely
Never mind, so it was
Video [1] -- [0..*] VideoAnalysis [1] -- [1..*] Clip