bendevski

bendevski

I’m playing around with elixir and solving some leetcode problems but I ran into an issue. The following code:

defmodule Solution do
  @spec climb_stairs(n :: integer) :: integer
  def climb_stairs(n) do
    climb_stairs(n, [1,0]) 
  end

  def climb_stairs(1, lis) do
    [first, second | _] = lis
    first + second
  end

  def climb_stairs(n, lis) do
    [first, second ] = lis
    climb_stairs(n-1, [first + second, second])
  end
end

always has lis be [1,0] (the result is always 1). Could someone explain what I’m doing wrong?

Showing Posts 1 to 3

benwilson512

benwilson512

Author of Craft GraphQL APIs in Elixir with Absinthe

Hi @bendevski welcome! It would be helpful if you could explain what this function is supposed to do.

LostKobrakai

LostKobrakai

You never actually change the list:

lis = [1, 0] # this is what you start with

# hitting the first clause of `climb_stairs/2` you do:
[1, 0 | _] = lis
1 + 0
# returns 1

# hitting the second clause of `climb_stairs/2` you do:
[1, 0] = lis
climb_stairs(…, [1 + 0, 0])
# calls `climb_stairs` again with `[1, 0]`
# eventually this reaches the first clause getting to the above case.
bendevski

bendevski OP

Thank you for the clear explanation. Mixed up the variables in my head and thought it was a language thing.

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