Regex Question: Given following string: "default via 10.141.23.1 dev eth0 \n10.141.23.0/24 dev eth0 proto kernel scope link src 10.141.23.235 \n169.254.169.254 dev eth0 \n172.17.0.0/16 dev docker0 proto kernel scope link src 172.17.0.1 \n"

I want to retrieve the following result: %{"default" => "10.141.23.1", "docker0" => "172.17.0.1"}

I can retrieve separately, like this: ~r/default via (?<default>\d+\.\d+\.\d+\.\d+)/ |> Regex.named_captures(str)

and ~r/dev docker0 proto kernel scope link src (?<docker0>\d+\.\d+\.\d+\.\d+)/ |> Regex.named_captures(str)
But I am not able to retrieve the desired result by combining both into one regex

e.g.

~r/default via (?<default>\d+\.\d+\.\d+\.\d+).*dev docker0 proto kernel scope link src (?<docker0>\d+\.\d+\.\d+\.\d+)/ |> Regex.named_captures(str)

returns nil