Silence logger in process?

Questions / Help
1

I build async task in a Mix task a little bit like this:

Task.async(fn -> MyApp.work() end)

This work function sometimes uses Mix.shell().info() to print informations, but I can make it silence using Mix.shell(Mix.Shell.Quiet), like this:

Task.async(fn -> 
   Mix.shell(Mix.Shell.Quiet)
   MyApp.work() 
end)

Is there something how I can make also Logger.info() output to not appear? Also maybe sometimes IO.puts ? I want this task to be silent. No logs, no STDOUT. Is this possible?

2

You can disable logs per process via Logger.disable(self()) (works only with self()). With STDOUT not really, however you can check out how ExUnit.CaptureIO works and maybe copy their solution.

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