cblavier
Hey there ![]()
I have the 2 following structs.
defmodule Variation do
@enforce_keys [:id, :attributes]
defstruct [:id, :description, :attributes, :slots, :block]
end
defmodule VariationGroup do
@enforce_keys [:id, :variations]
defstruct [:id, :description, :variations]
end
I would like to pattern match both structs at once, based on the fact they share similar attributes: :id and :description.
Is this achievable through behaviors?
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First 9 of 9 Posts
JohnnyCurran
Just treat them as maps:
And if you need to access the underlying module:
fuelen
Another options:
cblavier
I will actually use both of your solutions.
Guard + map attribute pattern matching
Thanks!
rvirding
Don’t you still have to know which one you have when you work with them?
cblavier
I have a general purpose loop that doesn’t need to know which one is which.
Then I also have specific functions that precisely pattern match against either
%Variation{}or%VariationGroup{}cblavier
I just realized that what I’m looking after is polymorphism for structs.
But I don’t think this is available in Elixir. Is it?
michallepicki
You can define a Protocol and have separate implementation for each struct
cblavier
But what if I also want an implementation that apply on both structs?
michallepicki
If you want to share the implementation of a function from a protocol, you can move it to a different module and delegate there from all separate protocol implementations. Or you can create a separate protocol for the shared parts and pass a list of struct modules (or primitive types if applicable) to
defimpl.