Laurent
In some tests, we need to compare 2 structs between each other. However when we build
- the test struct: this is done manually
%{
data_actions: %{A, B}
}
- the core struct, we go through a
data_actions |> Map.from_struct() |> Enum.reduce( ...)
Since OTP 26, Maps aren’t ordered anymore (Taking Control of Map Sort Order in Elixir · The Phoenix Files) so the result is random (in the resulting struct, the data_actions have a random order).
Is there any way to compare a struct recursively, without considering the values order? What is the elixir way to do it clean?
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hubertlepicki
to clarify: you want to compare two maps, not two structs?
Laurent
concretely yes, but recursively
dimitarvp
Not sure I understand the problem? Can you give an example of which comparison is failing?
christhekeele
The
==operator does not care about order when comparing maps. This applies for structs too.For tests, you can just
assert map1 == map2as you would expect.cevado
just adding to that, if you’re talking about tests… if you pattern match you can just look for the stuff you care for in a particular test run… so that works
stefan_z
Hi @Laurent,
If I understand your problem properly I would like to suggest this approach.
Let’s say we have
map_a = %{a: "a", b: "b", c: "c"}andmap_b: %{a: "a", b: "b", c: "no_match"}We could use
Enum.reduce_while/3to iterate throughmap_aand comparekeyandvaluefrommap_awith thekeyandvalueofmap_b.I hope this will help you
hubertlepicki
can you give me some example of map comparison that is failing? It should not be failing even if the order of fields looks different for some reason.
benwilson512
Again, what is wrong with a simple map_a == map_b ?
stefan_z
Absolutely nothing

==operator is the best way to do it. For some reason my brain went for a more complex approach