tio407
In the below function, I’m trying to see what value is being passed in el but for some iex throws an error (see below).
list
|> Enum.reduce([], fn el, acc ->
[[el] | acc]
|> IO.inspect()
|> List.flatten() # output: ["Y", "L", "B", "A", "R", "T", "S", "N", "O", "M", "E", "D"]
|> IO.inspect(el)
end)
ERROR:
iex(19)> Isogram.isogram?("DEMONSTRABLY")
** (FunctionClauseError) no function clause matching in IO.inspect/3
The following arguments were given to IO.inspect/3:
# 1
:stdio
# 2
["D"]
# 3
"D"
Attempted function clauses (showing 1 out of 1):
def inspect(device, item, opts) when is_list(opts)
(elixir) lib/io.ex:399: IO.inspect/3
(elixir) lib/enum.ex:1948: Enum."-reduce/3-lists^foldl/2-0-"/3
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First 7 of 7 Posts
NobbZ
Because
IO.inspect/3expects a keywordlist of options where you passed itel, which seems to be a string.Probably you wanted to do this instead?
tio407
When I do that, I get this. What does the error mean?
NobbZ
That you somewhere do not have a list, where a list is expected.
Can you show more of the code and also show the input?
tio407
This is the code:
Sample input and result:
Isogram.isogram?("DEMONSTRABLY")["Y", "L", "B", "A", "R", "T", "S", "N", "O", "M", "E", "D"]Took off the problematic part where I inspect each element in the list so it wouldn’t throw error.
NobbZ
accwill already be a flattened list, when you get into the second iteration.And you can not flatten down
[["E"], "D"]. What you actually want is properly building your accumulator by not wrappingelinto a list.|> Enum.reduce([], fn el, acc -> [el | acc] end)should totally do. (and could even be written as|> Enum.reduce([], &[&1 | &2]))tio407
I’m still unable to do
IO.inspect(el)at the end. The idea is that within the reduce function, I would check if the element currently being passed in, is in the accumulator already. If yes, return false. If not, continue.idi527
You might find
Enum.reduce_while/3useful.