ayhan.rashidov
Hello guys I have made an elixir http rest api using Maru. My requests are processed through a separate module using Genserver. Everything is working fine but I need to make the requests work synchronically without waiting each other. They have to be able to use the GenServer’s functions at the same time not one by one. I cannot use cast as I have to return a response. When one of the requests enters the GenServer.call the other one waits and enters after the first one has finished.
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voughtdq
You could do something like
ayhan.rashidov
Here is an example.
HTTP Server.
The GenServer module.
peerreynders
You don’t even have to reply in another process. The trick is that
handle_calldoesn’t have to reply immediately. So the state of the call can be stored in theGenServerstate and once the reply is readyGenServer.reply/2can be used to complete the call. Just remember that on the client side there is a timeout.aseigo
If they do not need to alter the state of the GenServer, then @voughtdq’s solution works fine (though they will still be serialized; but the time they block each other will be minimal, just the time require to spawn the process and return from handle_call).
The caveat in @voughtdq’s approach is that the requests can not change the state of the GenServer. So as long as the GenServer’s state is immutable with respect to the requests, that will work quite fine until you really start hammering it with requests (.. and then, the handle_call is unlikely to be the bottleneck).
If requests do need to change the GenServer’s state, then you need a different solution, though it will also involve spawning multiple processes so they can service requests in parallel.
Additionally, that approach offers no mechanism for back-pressure or rate-limiting on its own, though it could be added …
ayhan.rashidov
I have already tried this but it is waiting before entering the handle_call. It is waiting where I call the Genserver.call function.
peerreynders
Edit: ignore.
calcis part of the client API, not the server processing.voughtdq
Wait, do you mean that the HTTP server is blocking?
ayhan.rashidov
Exactly. It is blocked and doesn’t accept more calls until the previous one has finished.
ayhan.rashidov
No, not the HTTP, the GenServer as @peerreynders already said.
peerreynders
Building Non Blocking Erlang apps
Also: Why does this simple GenServer timeout? - #4 by peerreynders
Your could for example launch the calculation call via
Task.async/1which gives you a%Task{owner: term(), pid: term(), ref: term()}. Store that together with the caller details in the GenServer state.When the task is done, you’ll get a
{ref,result}viahandle_infoand you can complete the call withGenServer.reply/2.For a cleaner result, also take care of the details like Task.await does, i.e. demonitor and process
:DOWNmessages