omerss2311
Hey! I have a function defined with default arguments like so:
def my_func(arg1, arg2 \\ %{}, arg3 \\ false)
I want to pass it as a variable, so I’m capturing it as &my_func/3. However, I want to be able to invoke it with only one or two arguments as well, but that gives an error saying “function with arity 3 called with one argument”. Is there a way to do this?
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LostKobrakai
You can look into mfa tuples and
apply.omerss2311
Got it, thanks. Is there a way to imitate this behaviour then? (without passing the arguments as a list or something like that)
LostKobrakai
Or in a bit other words. Default arguments simplify function definition, but they don’t change how functions are called or referenced.
&my_func/3captures the arity 3 version of the created functions as shown by @D4no0.D4no0
Default arguments are just a syntactic sugar that transforms into functions with different arity:
So if you choose
my_func/3, then you are required to pass all arguments when calling it, if you want to avoid passing all the arguments use eithermy_func/1ormy_func/2.