Sebb

Sebb

I just tried to create a struct without fields (because: why not?).
It’s not possible with defstruct, which insists on an argument.

Best it can do is

defstruct _: nil # nice

btw, this is not OK:

defstruct [_]

isn’t that inconsistent?

So I tried to figure out what defstruct does. From the docs:

To define a struct, a developer must define both __struct__/0 and __struct__/1 functions. defstruct/1 is a convenience macro which defines such functions with some conveniences.

Where are __struct__/x documented?

Structs are usually defined with the Kernel.defstruct/1 macro

What if I want to be unusual? How can I define a struct by hand, maybe even without fields?

Marked As Solved

NobbZ

NobbZ

Using an empty list as argument to defstruct/1works for me:

iex(1)> defmodule S do
...(1)>   defstruct []
...(1)> end
iex(2)> %S{}
%S{}

Also Liked

aiwaiwa

aiwaiwa

One legitimate reason would be to implement a protocol without data.

Use case: postgrex/lib/postgrex/parameters.ex at v0.16.5 · elixir-ecto/postgrex · GitHub

dimitarvp

dimitarvp

…but what’s your goal?

sheharyarn

sheharyarn

Like @Nobbz said, you can just do this:

defmodule X, do: defstruct []

The reason this doesn’t work is that you cannot assign _. The first example works because :_ is not _, so you can do defstruct [:_] which is equivalent to your first example.


This is the macro that’s called underneath when defining a new struct. Going over the definition should help you better understand manually defining a struct in a module.

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