lud

lud

In order to only have one branch of code in a macro that defines functions with support for guards, I would like to always have a guard.

So I want to define the generated functions as def myfun(arg1,arg2) when true do when no guard is given.

I suspect that the compiler will get rid of it and that it will not impact performance, but I am not sure how to verify that.

Thank you.

Showing Posts 1 to 4

al2o3cr

al2o3cr

You can use the :S option to @compile to cause Elixir to dump a text representation of the generated bytecode.

For this module (in foo.ex):

defmodule Foo do
  @compile :S

  def without_guard(x) do
    x + 1
  end

  def with_guard(x) when true do
    x + 1
  end
end

Compiling it with elixir foo.ex produces a CompileError - that’s expected, because the @compile :S has caused the compiler to stop midway. The relevant bit of the result in foo.ex.S:

{function, with_guard, 1, 11}.
  {label,10}.
    {line,[{location,"foo.ex",8}]}.
    {func_info,{atom,'Elixir.Foo'},{atom,with_guard},1}.
  {label,11}.
    {line,[{location,"foo.ex",9}]}.
    {gc_bif,'+',{f,0},1,[{x,0},{integer,1}],{x,0}}.
    return.


{function, without_guard, 1, 13}.
  {label,12}.
    {line,[{location,"foo.ex",4}]}.
    {func_info,{atom,'Elixir.Foo'},{atom,without_guard},1}.
  {label,13}.
    {line,[{location,"foo.ex",5}]}.
    {gc_bif,'+',{f,0},1,[{x,0},{integer,1}],{x,0}}.
    return.

Other than labels and line numbers, with_guard and without_guard produce identical bytecode.

20
Post #1
christhekeele

christhekeele

That’s a neat trick, thanks for sharing!

harrisi

harrisi

I’ll also add that, in my experience, adding guards tends to increase performance, not decrease. In some cases it can be a significant speed increase.

Always crucial to profile actual code, though!

lud

lud OP

Ah yes I forgot about the S thing. I remember there was also an E format. I should take some time to learn about those.

Thank you :slight_smile:

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