lud
In order to only have one branch of code in a macro that defines functions with support for guards, I would like to always have a guard.
So I want to define the generated functions as def myfun(arg1,arg2) when true do when no guard is given.
I suspect that the compiler will get rid of it and that it will not impact performance, but I am not sure how to verify that.
Thank you.
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al2o3cr
You can use the
:Soption to@compileto cause Elixir to dump a text representation of the generated bytecode.For this module (in
foo.ex):Compiling it with
elixir foo.exproduces aCompileError- that’s expected, because the@compile :Shas caused the compiler to stop midway. The relevant bit of the result infoo.ex.S:Other than labels and line numbers,
with_guardandwithout_guardproduce identical bytecode.christhekeele
That’s a neat trick, thanks for sharing!
harrisi
I’ll also add that, in my experience, adding guards tends to increase performance, not decrease. In some cases it can be a significant speed increase.
Always crucial to profile actual code, though!
lud
Ah yes I forgot about the
Sthing. I remember there was also anEformat. I should take some time to learn about those.Thank you