eksperimental
Is there a way to conditionally import a function, but make the import available outside the if or case?
this obviously works:
def foo() do
import Enum, only: [map: 2]
map(1..5, &IO.inspect(&1))
end
this works as well:
if is_integer(term) do
import Enum, only: [map: 2]
map(1..term, &IO.inspect(&1))
end
this does not work due to lexical scope.
if true do
import Enum, only: [map: 2]
end
map(1..integer, &IO.inspect(&1))
So far so good.
My question is, how can we import conditionally at runtime, and make the import available outside the condition clause.
The only solution that I thought it could make it work was this, it does not and it baffles me.:
true && (import Enum, only: [map: 2])
map(1..integer, &IO.inspect(&1))
Note: for my use case I can solve this by running the condition at compile time, but I am just trying to understand how to do it at runtime.
Thank you
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al2o3cr
The behavior makes sense if you look at the implementation:
https://github.com/elixir-lang/elixir/blob/74bfab8ee271e53d24cb0012b5db1e2a931e0470/lib/elixir/lib/kernel.ex#L3791-L3803
The right-hand expression in
&&winds up inside acasestatement, so theimportdoes not leak out.Also Liked
LostKobrakai
That’s what I’d do, which seems a lot cleaner than conditionally importing things.
ityonemo
Imports are compile-time.
dimitarvp
Elixir being FP I don’t see any other way except closures or just passing a function like so
Or you can do it with a keyword list parameter with
:doand:elselike theifmacro does.Last Post!
eksperimental
@al2o3cr you are so right! I wrongly assumed that it was &&/2 was inlined by the compiler. I guess it all comes down to this, anyway had it been, it would have been the same:
because this seems to work the same way.
So I guess the only option here is evaluating the condition at compile time.
Thank you all guys for your contributions.