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Nobody’s doing Advent of Code this year? :smile:
I might do the first week or so.
For Day 1, first I solved it using regular expression...
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Setting this down for the night, as after a quick naive solve for quick part 1 I realize that part 2 is by design computationally expensi...
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The second part of today’s puzzle is very misleading.
FYI, each of the ghosts has only one possible position that ends with a "Z" on its...
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I tried to use combinatorial to solve today’s puzzles but failed (my brain burned out :exploding_head:). In the end I just used brute for...
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I spent 3 hours struggling in part 2, until I noticed a very basic mistake :joy:
Here’s my code:
By the way, the starting position in...
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Thought I’d kick today’s thread off!
Parsing
Enum rocks, so most of my code was actually in parsing input.
▶ Preprocessing input
Part 1...
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Don’t know why the regex ~r/[\W && [^\.]]/x does not work in Elixir. It works pretty well in Ruby.
Anyway, here is my solution:
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I mapped both the cards and every possible hand to numeric values and sorted them. In part 2 I could only think of replacing the jokers w...
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Hello all, hopefully I post this before someone else does and I don’t dupe.
IMO Day 4 was much easier than Day 3 (yay, I can sleep befor...
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So… that’s it? Everyone is stuck on part 2? :slight_smile: I looked at Reddit hints and thought I probably wouldn’t have come up with the...
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My solution finishes both parts in 5 seconds on my computer. That time should be possible to reduce by optimizing my rather naive tilt/2 ...
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This was way too easy after the last few days. Simple map, filter and count.
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Fairly straightforward Dijkstra’s algorithm
import AOC
aoc 2023, 17 do
def compute(input, candidates) do
{{max_row, max_col}, ite...
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I confess that I asked ChatGPT about the math. It gave me a name of an algorithm called the Shoelace formula. I still have to pay attenti...
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For Part 1, I was lazy and didn’t want to maintain variables and pass them down to each function (which would also involve merging two di...
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Trending Over Three Years
This one lost me at the beginning, but after a little inspection of the input, there is a clear path to the answer.
Explainations in par...
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A rather verbose solution but simple enough I guess.
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After looking up the formula for calculating an intersection of two lines on wikipedia, part 1 was straightforward. I really do not know ...
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My code for today’s puzzle:
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Fun day today! Quite straightforward but the key observations are:
SpoilersFinding the column-wise reflection line is the same as transp...
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I came up with a solution myself, but it is not fast.
My first brute-force solution simply tried removing all combinations of three edg...
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For part 2 I transformed the map into a graph because I wanted to see it and check if there was a bottleneck point or something.
But no,...
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I went for a brute-force solution, implementing the most straight-forward algorithm I could think of. That initial implementation solved ...
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Got top 1000 for part 1, part 2 was super long so I took a while to understand it. Pretty fun day overall!
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Since I keep 1 notebook for all days and didn’t see any threads in this style I’ll create this one.
If anyone does the same style, it wi...
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