BorjaEst

BorjaEst

Trees (specially gb_trees) are a very efficient/fast tool to store Key-Value. However, depending on the program it’s usage cat get a bit more complicated.

Here goes my challenge.
What would be the most efficient way to get a random element and it’s path from a gb_tree?

Showing Posts 1 to 3

al2o3cr

al2o3cr

:gb_trees.iterator/1 plus a reservoir sampling algorithm?

BorjaEst

BorjaEst OP

The idea is good if we don’t want to cover the whole tree (just the k first), however to cover the whole tree, wouldn’t we have to execute rand:random() in each iteration (rand operations are quite expensive)?

BorjaEst

BorjaEst OP

So after thinking about it, my solution would be something like this:

iex(1)> tree = :gb_tree.example() #Any f that returns a tree
{3, {:a, 1, nil, {:b, 2, nil, {:c, 3, nil, nil}}}}
iex(2)> n = :rand.uniform(:gb_trees.size(tree))
2
iex(11)> iter = :gb_trees.iterator(tree) 
[{:a, 1, nil, {:b, 2, nil, {:c, 3, nil, nil}}}]
iex(14)> {k,v,_}=Enum.reduce(1..n, {:nil,:nil,:gb_trees.iterator(tree)}, fn _, {_,_,i} -> :gb_trees.next(i) end)
{:b, 2, [{:c, 3, nil, nil}]}

However I am thinking, now gb_trees are not used any longer as we do have maps.

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