amirOrbe

amirOrbe

Hi everyone, I have a function with two parameters with default values something like:

def(param1 \\ %{}, param2 \\ "") do
###
end

this is the best practice for do that? or you know another way ?

Most Liked

zachdaniel

zachdaniel

Creator of Ash

I’ve learned the hard way that if you ever have more than one optional argument its a smell and you should refactor it to an opts list :smiley:

21
Post #2
srcoulombe

srcoulombe

You can also use functions from the Keyword module

def foo(opts \\ []) do
    arg1 = Keyword.get(opts, :arg1, "default_value") 
    ...
end
dimitarvp

dimitarvp

Absolutely never do this. Your colleagues or even your own future self will forget or be in a hurry just once and introduce a bug that would be difficult to track down.

Either only one optional argument and it must 99% of the time be the last one – unless the differences in type will make it completely obvious if something goes wrong – or use a keyword list as others have said. That approach also allows you to easily name stuff f.ex.

do_stuff(repo, changeset, username: "amir", password: "nope", dob: ~D[2000-01-01])

Last Post!

dimitarvp

dimitarvp

Oh, I am not against keyword lists as options, of course. That’s one of the gems in Elixir: it allows you to emulate named function arguments and it is super convenient!

My objection is towards more than one optional function argument (i.e. 2 or more having default values). That becomes messy super quickly.

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