fnux
Hello !
I was expecting :crypto.block_encrypt :aes_ige256 to be symmetric, I don’t get what’s wrong. Can someone enlighten me ?
Here is an example script :
data = <<666::size(256)-unit(8)>>
tmp_aes_key = <<1234567890::size(32)-unit(8)>>
tmp_aes_iv = <<0987654321::size(32)-unit(8)>>
encrypted = :crypto.block_encrypt :aes_ige256, tmp_aes_key, tmp_aes_iv, data
decrypted = :crypto.block_decrypt :aes_ige256, tmp_aes_key, tmp_aes_iv, data
IO.puts "-- Initial Data --"
IO.inspect data
IO.puts "-- Encrypted --"
IO.inspect encrypted
IO.puts "-- Decrypted --"
IO.inspect decrypted
And its output :
-- Initial Data --
<<0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, ...>>
-- Encrypted --
<<13, 146, 170, 197, 88, 244, 100, 48, 180, 234, 28, 168, 36, 10, 88, 225, 15,
232, 33, 201, 90, 37, 54, 105, 155, 70, 166, 40, 128, 12, 107, 11, 234, 61,
80, 202, 89, 18, 222, 125, 127, 133, 98, 236, 28, 107, 254, 155, 130, 223,
...>>
-- Decrypted --
<<200, 243, 4, 223, 10, 44, 240, 101, 171, 77, 103, 159, 39, 239, 138, 91, 108,
248, 162, 162, 228, 170, 138, 113, 98, 56, 248, 183, 167, 19, 123, 243, 162,
144, 214, 253, 136, 98, 37, 210, 14, 108, 56, 31, 33, 222, 148, 228, 183, 8,
...>>
Thanks !
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OvermindDL1
Shouldn’t
datahere beencrypted?fnux
Ow, my bad. tired
OvermindDL1
Hehe, happens to us all. ^.^
Also you can click the checkmark on a post to mark that post as the one that resolves the issue.
slouchpie
For posterity: don’t use
:crypto.block_encryptfor anything new you are writing.Instead, use
:crypto:crypto_one_time.See here for info: New and Old API — OTP 29.0.2 (crypto 5.9)
ijunaidfarooq
Hi, I had these 2 methods
I am trying make them work with
:crypto:crypto_one_time/4, 5When I do this
it says:
# Erlang error: {:badarg, {'api_ng.c', 141}, 'Unknown cipher'}any clue?
voltone
The new API only accepts the algorithm atom values listed in the latest
:cryptomodule docs. So:aes_cbc256should be:aes_256_cbc.ijunaidfarooq
but how a same module can do encrypt and decrypt both?
just the last flag for true and false will decide ? its ecrypt or decrypt ?
voltone
Yes, the last argument is actually an option list, so you could do:
Passing
trueorfalseinstead is just a shortcut.ijunaidfarooq
thank you.
al2o3cr
IMPORTANT: unless this code is called with a different value in
SNAP_IVevery time, there is a potential security hole when reusing an IV with CBC: