RazgrizHsu
Hi, all,
i’m trying compare with timex variables,
but i don’t know why this code work like that..
dts = Timex.parse!( "2019-01-01T00:00:00.000Z", "{ISO:Extended:Z}" )
now = Timex.parse!( "2019-01-01T00:00:00.100Z", "{ISO:Extended:Z}" )
dt = Timex.shift( dts, seconds: 5 )
if ( dt <= now ) do
raise ( "why? dt already shift seconds... dt[#{ inspect dt }] now[#{ inspect now }]" )
else
:ok
end
I thought that such a comparison should be the opposite result…
anyone can help me to understand this? thanks
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RazgrizHsu
This is indeed a very good suggestion, thank you
NobbZ
I tend to always use the regular comparison operators against
0.This does match semantics very well.
RazgrizHsu
okay thank you guys,
so i need change my code to
right?
@kip thank you for explanation
i was wrong a test to make sure my project working… but seem not work
I need to add this paragraph to remind me of myself
thanks guys
kip
The built in comparison operators aren’t the right tool for this job. You probably want to use Timex.compare/3.
For an explanation of why this is the case you might find this useful. Especially this quote:
NobbZ
You need to use
Timex.compare/2/3instead ofKernel.<=/2.