spammy
Say we have a function:
def func(a, b \\ 0) do
I believe this generates func/1 and func/2. Is it possible to make func/2 private without spinning out a helper/implementation/do_func/2 equivalent?
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First 7 of 7 Posts
dimitarvp
Does not seem to be possible, no.
al2o3cr
You can mix
defanddefpwith different arities:spammy
That is where I landed, that the default parameter has to be expressed differently.
Would it be more idiomatic to change the name of the private function?
LostKobrakai
I’d say yes. It’s just accidental that the private one happens to have a different arity, which allows for it being named the same.
rvirding
This is just because what defines a function is its module, name and arity. So
foo/1andfoo/2are 2 different functions that just happen to have the same name.spammy
I guess my more general question was “is it possible to affect implied functions created by default parameters”. An example that doesn’t work:
sodapopcan
I’ve always found it helpful to think of
\\as a simple convenience rather than “default arguments.” All it’s doing is turning this:into this:
The easiest and clearest way to get what you want it to just write it out manually as suggested.
So the short answer is no, but technically yes if you consider redefining
defand changing how\\works