vitalydolgov
I have a question on pattern matching in case. This function
def f(map) do
case map do
%{a: i} -> i
%{} -> :empty
_ -> :other
end
end
works in this way:
> f(%{a: 67})
67
> f(%{b: 67})
:empty
> f(%{})
:empty
Can anybody explain me why it matches on the second clause, when non-empty map provided? I’m on Elixir 1.11.
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RudManusachi
Hi @vitalydolgov
And welcome to the community!
%{}matches any map.To match against empty map you could use either
map_size/1function or compare with%{}explicitly in guard as:dsounded
Hey
But basically you just need to use a guard for the second case
Werner
It is also in the hexdocs the reference for it, in the section on maps:
“Note that the empty map will match all maps,…”
https://hexdocs.pm/elixir/master/patterns-and-guards.html
vitalydolgov
Thank you