hariharasudhan94
How to use return statement with if condition in elixir?
lets say i have a sample like
a = 20; b = 10;
if (a > b) do
{:ok, "a"}
end
if (a < b) do
{:ok, b}
end
if (a == b) do
{:ok, "equal"}
end
when i run this code first condition satisfied ,instead of returning {:ok, "a"} tuple it starts executing next block of code, how can i stop the execution once first condition is met, and return result
Marked As Solved
LostKobrakai
You can’t return early in elixir, but there’s another constuct for such operations:
cond do
a > b -> {:ok, "a"}
a < b -> {:ok, "b"}
a == b -> {:ok, "equal"}
end
Also Liked
OvermindDL1
To be more specific, there are no statements, everything returns something, including those lines, they just return it ‘up’ (so the if returns it, but the if is not being assigned to anything so it vanishes). 
peerreynders
Just to add to the spectrum (i.e. I’m not recommending this) I see Greg’s suggestion as a “cleaned up” version of
a = 20
b = 10
result =
case {a,b} do
{c,c} -> "equal"
{c,d} when c > d -> "a"
{c,d} when c < d -> "b"
end
reply = {:ok, result}
IO.inspect(reply)
which could also be written as
a = 20
b = 10
result =
case {a,b} do
_ when a > b -> "a"
_ when a < b -> "b"
_ -> "equal"
end
reply = {:ok, result}
IO.inspect(reply)
leading to the accepted solution
a = 20
b = 10
result =
cond do
a > b -> "a"
a < b -> "b"
true -> "equal"
end
reply = {:ok, result}
IO.inspect(reply)
And if do always has a “second” value it evaluates to when the condition is false - it will return nil
a = 10
b = 20
value1 =
if a > b do
"a"
end
value2 =
cond do
a > b -> "a"
true -> nil
end
IO.inspect({value1,value2})
> {nil, nil}
gregvaughn
You could use a cond, as shown above, or even different named function heads with pattern matching
def compare(a, a), do: {:ok, “equal”}
def compare(a, b) when a > b, do: {:ok, “a”}
def compare(a, b) when a < b, do: {:ok, “b”}







