przemyxe0p
Hi,
I am wondering why my solution wil not work
1. source: Perfect Numbers in Elixir on Exercism
2. solution attempt:
@spec classify(number :: integer) :: {:ok, atom} | {:error, String.t()}
def classify(number) do
case aliquot_sum(number) do
number -> ok(:perfect)
x when x > number -> ok(:abundant)
x when x < number -> ok(:deficient)
end
end
defp ok(item), do: {:ok, item}
defp aliquot_sum(number), do: get_divisors(number) |> Enum.sum()
defp get_divisors(number, divisor \\ 1, acc \\ [])
defp get_divisors(number, divisor, acc) when divisor > div(number,2), do: acc
defp get_divisors(number, divisor, acc) when rem(number, divisor) == 0,
do: get_divisors(number, divisor + 1, [divisor | acc])
defp get_divisors(number, divisor, acc), do: get_divisors(number, divisor + 1, acc)
end
3. question:
Complier is saying:
this clause cannot match because a previous clause at line 15
always matchesElixir
perfect_numbers.ex(15, 7): related
and
variable "number" is unused (there is a variable with the same name in the
context, use the pin operator (^) to match on it or prefix this variable
with underscore if it is not meant to be used)Elixir
Why is that, why it cannot match with number passed to function?
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al2o3cr
This form rebinds the name
numberinside the case branch:This will match ANY integer passed to
some_fun.ON THE OTHER HAND
Using the pin operator says “match this existing value”:
That will only match if
some_funis passed 0, since2*0 == 0sodapopcan
Oh sorry wasn’t responding specifically to your question.
But to answer it: Elixir allows variable re-binding, ie, you can say:
number = number+ 1and not get an error thatnumberis already defined. Like=,->is also a binding operator, so when you saynumber -> ok(:perfect),numberis rebound. The match on the value ofnumber, you need to use the pin operator.przemyxe0p
Ok, I get it, but the question was, why it was not working with case this, matching why do we have to use this ^ pin operator?
sodapopcan
People have a weird aversion to
condfor some reason that I don’t really understand. Doing pure boolean checks is exactly what it exists for. Thecaseversion is essentially the same with unnecessary extra syntax. Usingcondgives added information that indeed all clauses are boolean checks. It’s only rare because this doesn’t come up as often in Elixir, but it certainly does come up!krasenyp
przemyxe0p
Last question, i cannot find explanatio why this works that way. Do you have explanation or link to resources?
krasenyp
In my experience it’s very rare to use
condbut it’s still valid.kokolegorille
Because it’s very rare to use ^number in the case
Yet, You can do as You like
przemyxe0p
After adding ^ operator it’s right why should I use cond? What is more “idiomatic” whatever this “idiomatic” word mean?
kokolegorille
No, your logic is wrong and number might not be what You think…
As soon as there is a match, the rest of the case is discarded
the number in the case is not the number parameter, it is a new number
You probably should write this with cond